pyspark.pandas.Series.to_frame

Series.to_frame(name: Union[Any, Tuple[Any, …], None] = None) → pyspark.pandas.frame.DataFrame[source]

Convert Series to DataFrame.

Parameters
nameobject, default None

The passed name should substitute for the series name (if it has one).

Returns
DataFrame

DataFrame representation of Series.

Examples

>>> s = ps.Series(["a", "b", "c"])
>>> s.to_frame()
   0
0  a
1  b
2  c
>>> s = ps.Series(["a", "b", "c"], name="vals")
>>> s.to_frame()
  vals
0    a
1    b
2    c